WebAnswer: Explanation: To avoid violating A → B, the new tuple either has to disagree with (0,0,0) on A (that is, the first component of the new tuple is not 0), or it must agree on B (i.e., the second component must be 0). In other words, the new tuple must be of the form (0,0,w), or (x,y,z) where x ≠0. WebJul 29, 2024 · Let R (ABCDEFGH) be a relation schema and F be the set of dependencies F = {A → B, ABCD → E, EF → G, EF → H and ACDF →EG}. The minimal cover of a set of …

Consider the relational schema given below, where eId of the …

WebConsider a relational schema R = (A, B, C, D, E, H) on which the following functional dependencies hold: {A → B, BC → D, E → C, D → A}. What are the candidate keys of R? huntington ny state farm

[Solved] Consider a relation R (A, B, C, D, E, F, G, H), where each a

WebConsider the relation scheme R(E, F, G, H, I, J, K, L, M, N) and the set of functional dependencies-{ E, F } → { G } { F } → { I , J } { E, H } → { K, L } { K } → { M } { L } → { N } … Webrelation R(A,B,C,D,E,F,G,H) with the following functional dependencies: A → BCD AD → E EFG → H F → GH (a) Based on these functional dependencies, there is one minimal key What is it? (b) One of the four functional dependencies can be removed without Which one? 5. relation R(A,B,C,D,E,F) with the following set of functional WebThe minimal cover G of F is: SIN ÿ E_Name SIN ÿ B_Date SIN ÿ Address SIN ÿ D_Num D_Num ÿ D_Name D_Num ÿ D_Manager To prove that two sets of functional dependencies F and E are equivalent, we either show that F+ =E+ or that E covers F and F covers E. To show that F covers E, we calculate X+ with respect to F for every FD XÿYinEandcheck huntington ny solar power providers