Dsepp math 2018
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Dsepp math 2018
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Web19. (a) f(x) = x2 −12kx−14x+36k2 +89k +53 = (x−(6k +7))2 +(5k +4)Therefore, the coordinates of Q is (6k +7,5k +4). (b) R = (7−6k,5k +4) (c)(i) Slope of QS = (5k +4)−(4−3k) (6k +7)−7 4 3, using point-slope form yields equation of QS: y −(4−3k) = 4 3 (x−7)ℓQS: 4x−3y −9k −16 = 0 (c)(ii) Let U be the centre of C. Note that QR is a horizontal line, also … WebDSEPP DSE Material
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